In an ap sum of first 10 terms is-150

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August undefined, 2024

WebMar 19, 2024 · Given that sum of the first 10 terms of an A.P. is -150. S10 = -150 And the sum of next 10 terms is -550. So, the sum of first 20 terms = Sum of first 10 terms + sum …

Sum of N terms of Arithmetic Progression Formula with Proof

WebApr 11, 2024 · Given the sum of the first 10 terms of an AP is -150 and the sum of the next ten terms which means Sum of first 20 terms-Sum of first 10 terms is -530.. Let the first term, common difference of the AP be a and d respectively. Now, ⇒ S₁₀ = 10/2 [ 2a + (10 - 1)d ] ⇒ -150 = 5 [ 2a + 9d ] ⇒ 2a + 9d =-30...(i)Now, according to the second case, WebSolution Here, we are given S 10 = -150 and sum of the next ten terms is −550. Let us take the first term of the A.P. as a and the common difference as d. So, let us first find a10. For … raymonde richer

In an A.P., the Sum of First Ten Terms is −150 and the …

WebJul 29, 2024 · In an AP, the sum of first ten terms is -150 and the sum of its next ten terms is -550. Find the A.P.I have provided the easiest solution of above question, ... WebWord problems: Sum to n terms of an arithmetic progression. It took Samia 20 20 minutes to write a 2 {,}300 2,300 word essay. She typed 20 20 words in the first minute. She increased the number of words by a constant, c c, every minute. WebOpen in App Solution Verified by Toppr From the question it is given that, The sum of the first 10 terms =−150 The sum of the next 10 terms =−550 A.P =? We know that, Sn … simplicity steam press

In an AP, the sum of first ten terms is -150 and the sum of …

WebSolution 1 Here , a = 2 , l= 29 and s n = 155 Let d be the common difference of the given AP and n be the total number of terms. Then, T n = 29 ⇒ a + (n-1) d = 29 ⇒ 2 + (n-1) d= 29 .............. (1) The sum of n terms of an AP is given by s n = n 2 [ a + l] = 155 ⇒ n 2 [ 2 + 29] = ( n 2) × 31 = 155 ⇒ n = 10 Putting the value of n in (i), we get: WebFind the first term, a 1 a_1 a 1 a, start subscript, 1, end subscript, of the sequence. raymond erarioWebIf its 10th term is 41, then find the sum of its first fifteen terms. Solution: Question 33. The 13th term of an AP is four times its 3rd term. If its fifth term is 16, then find the sum of its first ten terms. Solution: Question 34. In an A.P., if the 12th term is -13 and the sum of its first four terms is 24, find the sum of its first ten terms. raymond eric

"WebIn the given AP, the first term is a = 7 and the common difference is d = 4. Let us assume that 301 is the n th term of AP. Then: T n = a + (n - 1)d 301 = 7 + (n - 1) 4 301 = 7 + 4n - 4 301 = 4n + 3 298 = 4n n = 74.5 But 'n' must be an integer. Hence 301 cannot be a term of the given AP. Answer: 301 cannot be a term of the given AP. " - In an ap sum of first 10 terms is-150

In an ap sum of first 10 terms is-150

WebApr 2, 2024 · The median of the distribution given below is 14.4. Find the values of x and y, if the sum of frequency is 20. Find the common difference ' d ' of an AP whose first term is 10 and the sum of the first 14 terms is 1505 . For what value of ' n ', are the nth terms of the APs : 9,7,5,….. and 15,12,9,…. the same? WebMar 12, 2024 · Sum of n terms in an arithmetic progression is given by the formula S = n 2 [ 2 a + ( n − 1) d] in which a = first term, n = number of terms and d = common difference. Let us understand this concept in brief by taking an example. Consider a man putting 100 rupees in his daughter’s piggy bank, in such a way that, He deposits 100 rupees on ...

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WebApr 8, 2024 · Given sum of first ten terms = $ - 150$ We know that Sum of n terms of AP ${S_n} = \dfrac{n}{2}[2a + (n - 1)d]$ Therefore, $\ \Rightarrow {S_{10}} = \dfrac{{10}}{2}[2a … Webasked Sep 14, 2024 in Mathematics by Mubarak (32.8k points) In an AP, the first term is -4, the last term is 29 and the sum of all its terms is 150. Find its common difference. arithmetic progression class-10 1 Answer +1 vote answered Sep 14, 2024 by AmirMustafa (60.3k points) selected Sep 23, 2024 by Vikash Kumar Best answer

WebSep 2, 2024 · Best answer i. Sum of first five terms = 150 Sum of the five consecutive terms of arithmetic sequence is five times of its middle term. Third term = 150 5 = 30 150 5 = 30 ii. First term + Tenth term = Second term + Nineth term = Third term + Eighth term = Fourth term + Seventh term = Fifth term + Sixth term = 550 5 = 110 550 5 = 110 WebOct 20, 2024 · Let a be the first term and d be the common difference of the given AP . S₁₀ = -150. ⇒ Sn = n/2 [ 2a + (n-1)d] ⇒ S₁₀ = 10/2 [ 2a + ( 10 - 1 ) d ]. ⇒ -150= 10/2 [ 2a + 9d ] ⇒ …

WebMar 27, 2024 · C. I Frequency 10 vicle, me ACB be 0-15 15-30 30-45 45-60 ore than type ogive' for the given data. 18 40 20 60-75 12 29) The sum of the reciprocals of Rehman's ages 3years ago and 5 years from now is Find his present age. WebThe sum of n terms of an AP can be easily found out using a simple formula which says that, if we have an AP whose first term is a and the common difference is d, then the formula of the sum of n terms of the AP is S n = …

Webin an AP of 50 terms ,the sum of first 10 terms is 210 and the sum of its last 15 terms is 2565 find the AP This question hasn't been solved yet Ask an expert Question: in an AP of 50 terms ,the sum of first 10 terms is 210 and the sum of its last 15 terms is 2565 find the AP

WebExpert Answers. hala718. Certified Educator. Share Cite. Le a1, a2, ..., a10 are terms of an A.P. given S10 = a1+a2+...+10 = 150. But we know that: s10 = (a1+a10)*10/2 = 150. ==> … raymond e purves foundationWebJul 29, 2024 · In an AP, the sum of first ten terms is -150 and the sum of its next ten terms is -550. Find the A.P.I have provided the easiest solution of above question, ...... raymond eric gravesWebYou would do the exact same process, but you would have to SOLVE for "n" (number of terms) first. To do so, you must start with the arithmetic sequence formula: tn = a + d(n −1) Then, sub in all known values. tn = 15 (last term of the sequence), a = 1 (first term), d = 2 (difference between terms) and solve for n like so: 15 = 1 + 2(n −1) simplicity steampunk coatWebThe sum of first 10 terms of an AP is -150 and the sum of its next 10 terms is -550. Find the AP. Solution Let a be the first term and d be the common difference of the AP. Then, It is … raymond eric carr kyWebThe sum of the first five terms of an AP and the sum of the first seven terms of the same AP is 167. If the sum of the first ten terms of this AP is 235, find the sum of its first twenty terms. Q. simplicity star wars pattern 4450WebJun 24, 2024 · In an A.P., the sum of first ten terms is −150 and the sum of its next ten terms is −550. Find the A.P. - 10761082 raymond erickson hudlWebGiven that sum of the first 10 terms of an A.P. is -150. S 10 = -150 And the sum of next 10 terms is -550. So, the sum of first 20 terms = Sum of first 10 terms + sum of next 10 terms S 20 = -150 + -550 = -700 Now, having S 10 = 10/2 {2a + (10 − 1)d} -150 = 5 (2a + 9d) -30 = 2a + 9d 2a + 9d = -30 . . . . (1) And, S 20 = 20/2 {2a + (20 − 1)d} raymond eric haight